Materials.Technologies.Tools

18

S.B. Karavashkin

Check the correspondence of (8) to (4). Conveniently use for it, basing on (9), the condition at which the regime betacut.gif (852 bytes) = 1 takes place. For the first equation of system we yield

(21)

For the nth equation

(22)

It is obvious from (21) and (22) that (8) also satisfies the system (4), the same as (6) and (7).

As the above calculations show, (6), (7) and (8), corresponding to all three mentioned regimes of vibration processes, completely satisfy all equations of the modelling system, by contrast to above conventional solution (2). With it, the given solutions are complete, because they cover the whole interval 0 equless.gif (841 bytes) betacut.gif (852 bytes) < infinity.gif (850 bytes).

One more distinction from the known solutions is that minimal changes in the model bring considerable changes in solutions; this can be easily proved by the example of infinite line.

2.2. Infinite line

The mechanical model of an infinite line is given in Fig. 5.

 

fig5.gif (3275 bytes)

Fig. 5. Mechanical model of infinite elastic lumped line

 

The system of differential equations describing this model has the form

(23)

The distinction of (23) from (4) is, the elements with negative numbers n appear in the line and, in this connection, the equation describing the line boundary (the first equation of system (4)) disappears from (23). As a result, instead three, the given system has two solutions related to the periodical regime at betacut.gif (852 bytes) < 1

(24)

and aperiodical one at  betacut.gif (852 bytes) > 1

(25)

The finite solution for critical regime is absent, and solutions themselves differ both in their amplitude and phase parts. The typical form of vibration for the periodic regime is given in Fig. 6.

fig6.gif (6700 bytes)

Fig. 6. The typical appearance of vibrations for the periodical regime ( = 15 Hz, F0 = 0,6 N, m = 0,01 kg, s = 100 N/m, a = 0,01 m, fcrit = 31,8 Hz,   lumbdacut.gif (836 bytes) = 0,064 m, lumbdacut.gif (836 bytes)crit  = 0,02 m)

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