V.6 No 4, pp 13 - 19 |
15 |
The features of inclined force acting | |
From this brief consideration we can see that inclined vibrations far from always arise due to nonlinear processes in an elastic system, as it was supposed before. Inclined waves can arise quite naturally under affection of a force inclined to the wave propagation direction. And this conclusion can be quite simply extended to a most wide spectrum of the vibration processes. 3. Trajectory of line elements motionDrawing our attention to the trajectory of elements motion, we see, this trajectory has a form of an ellipse circumscribed around the point of rest of the element. And the wave inclination is formed due to the shift phase of the element-to-element motion along these elliptic trajectories. This vibration structure is well-known in physics, particularly in wave processes in unbounded volumes of liquid. In a wave, the motion of liquid is non-stationary. So the trajectories of separate particles are far from being time-coinciding with the lines of current. They have absolutely other shape. With the small amplitudes they are circumferences in a great approximation. We find these circular trajectories both on a surface and in depth of liquid. Only in the most upper layers the diameters of circular ways are largest [4, p. 300- 301]. Indeed, the spatial vibration processes have their peculiarities. None the less, it is typical that the basic regularities can be run down already in a 1D model. It also follows from the yielded solutions that the elements vibration ellipsoidal pattern retains as in the critical as in aperiodical regimes. Due to it, in this last case there in the line forms a complex wave fast-damping along the line, and this is one more feature that the exact analytical solutions demonstrate. 4. The new class of functions being the solution of the wave equation We can extend the above generalisation also to the solution of the wave equation on the whole. It is known that the hyperbolic-type differential equation |
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(12) |
has general solution [5, p. 300] | |
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(13) |
where c = ![]() |
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(14) |
here For it, basing on the known laws of implicit functions differentiation, find first and second particular derivatives of (14) with respect to x and t. To simplify the calculation, consider a half of the right part of (14) |
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(15) |
where |
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The first derivatives have the form |
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(16) |
The second derivatives after transformation and substitution of expressions (16) take the form |
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(17) |
Substituting (17) into (12), yield the required. Similarly we can prove the second part of expression (14) to be corresponding to the equation (12). |